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Editorial
Let $R'$ be the reflection of $R$ about center of the circle. Then work on parallelogram $RSR'T$.
Let $PQ$ be a diameter of a circle and let $R$ be a point on the segment $PQ$ such that $PR:RQ=6:7$. Let $S$ be a point on the circle such that $SR$ is perpendicular to $PQ$. Let $ST$ be the diameter through $S$. If $[XYZ]$ denotes the area of the triangle $XYZ$, find $\frac {[PQS]}{[RST]}$ to the nearest integer.
Let $R'$ be the reflection of $R$ about center of the circle. Then work on parallelogram $RSR'T$.