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In a $\triangle ABC$ a normal is drawn at point $D$ from point $A$ to $BC$. Given that,
$(i)\space AC = 3×AB$
$(ii)\space BD = 1$
$(iii) ∠CAD = 3∠BAD$
Find the value of $CD$.Geometry
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$(i)\space AC = 3×AB$
$(ii)\space BD = 1$
$(iii) ∠CAD = 3∠BAD$
Find the value of $CD$.