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Let $ABCD$ be a square. $M$ is a point on the segment $AD$, and $N$ is a point on the segment $DC$ such that $\angle BMA = \angle NMD = 60^{\circ}$. Find the value of  the angle $\angle MBN$.


Geometry  


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Attempt 23


Solve 13


First Solve mollamdkashem22