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Let $D$ be the intersection of $PS$, $QT$, and $RU$ of $\triangle{PQR}$ where $S$, $T$, and $U$ are points respectively on $QR$, $PR$ and $PQ$. If $DS=DT=DU=3$ and $PD+QD+RD=43$, then $PD.QD.RD=?$
Geometry
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Let $D$ be the intersection of $PS$, $QT$, and $RU$ of $\triangle{PQR}$ where $S$, $T$, and $U$ are points respectively on $QR$, $PR$ and $PQ$. If $DS=DT=DU=3$ and $PD+QD+RD=43$, then $PD.QD.RD=?$
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