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Subtracting the second equation from twice the first equation gives $ab=2a-b$ so that $b=\frac{2a}{a+1}$
Now you've to solve the equation with these
Dissolving the equation
Find the sum of all real numbers $a,b$ satisfying the following system of equations
$$2a^2 -2ab+b^2 =a$$
$$4a^2 -5ab +2b^2 =b$$
Equation
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