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Let $p,q,r,s>0, p^2+q^2=r^2+s^2$ and $p^2+s^2-ps=q^2+r^2+qr$. The value of $\frac{pq+rs}{ps+qr}$ can be expressed as $\frac{\sqrt{a}}{b}$, where $a,b$ are coprimes. Find $a+b^2$.

Geometry

Equation

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