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Editorial
Divide $y(x+y)^2=9 $ by $y(x^3-y^3)=7$ and then expand $x^3-y^3$, cancel out the common factors.
Solve the system of equations & find out $(x+y)$.
$$y(x+y)^2=9 $$
$$y(x^3-y^3)=7$$
Divide $y(x+y)^2=9 $ by $y(x^3-y^3)=7$ and then expand $x^3-y^3$, cancel out the common factors.